let m and n bel positive integers such that the fraction m/n is irreducible and the fraction 4m+3n/5m+2n is not irreducible. Find the greatest common divisor of 4m+3n and 5m+2n
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given the fraction 41/77 .Find a whole number a such that when a is added to both of the numerator and the denominator of the fraction ,the resulting new fraction is equal to 4/7
FIND all the natural numbers a and b such that
the product of "largest common divisor" of (a,b) and "lowest common multiple" of (a,b) is 510510.
tricky problem
the sum of denominator and numerator of a fraction is 121 and the fraction is equal to 4/7.Find the denominator of the fraction ?
Tổng của mẫu số và tử số bằng 121 phân số đó bằng 4/7 tìm mẫu số
Tổng số phần bằng nhau : 4+7=11
Mẫu số là : 121 : 11 nhân 7 = 77
Đ/S:77
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77 ddos minhf lamf rooif ddungs 100 %
Exer 1: There is a division with the quotient is 6 and the remainder is 3. The sum of dividend, divisor and remainder are 195. Find the dividend are divisor.
Exer 2: Prove that: Amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3: Given natural number, n overline{1ab1}. Let m be the natural number which is written the opposite respectively of n. Prove that the different of n and m divisibles by 90.
Đọc tiếp
Exer 1: There is a division with the quotient is 6 and the remainder is 3. The sum of dividend, divisor and remainder are 195. Find the dividend are divisor.
Exer 2: Prove that: Amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3: Given natural number, n = \(\overline{1ab1}\). Let m be the natural number which is written the opposite respectively of n. Prove that the different of n and m divisibles by 90.
Exer 1:
Trả lời:
The sum of dividend and divisor are:
195 - 3 = 192
Because the quotient is 6.
The divisor is:
(192-3) : (6+1) = 27
The dividend is:
192 - 27 = 165
Exer 2:
Trả lời:
Let three unknow numbers be: n, n + 1, n + 2.
Because n has three forms: 3k, 3k + 1, 3k + 2.
+) If n
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Xin lỗi, mình vẫn chưa viết xong, rồi mình viết tiếp đây:
+) If n = 3k then there is only n divisibles by 3.
+) If n = 3k + 1 then there is only n + 2 divisibles by 3.
+) If n = 3k + 2 then there is only n + 1 divisibles by 3.
Thus, amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3:
Trả lời:
When we written the opposite respectively of n, we obtain \(\overline{1ba1}\).
We have:
\(\overline{1ab1}\) + \(\overline{1ba1}\) = (1000 + 100a + 10b + 1) - (1000 + 100b + 10a + 1)
= 90a - 90b
= 90(a - b)\(⋮\) 90
Thus, the difference of n and m which divisibles by 90.
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Let a, b and c be positive integers. The sum of 160 and the square of a is equal the sum of 5 and
the square of b. The sum of 320 and the square of a is equal to the sum of 5 and the square of b.
Find a.
1.Find the greatest negative integer value for n so that:
n4 - 25n2 - 70n - 49
2.Toán tiếng anh: If the length of a leg of a right angle is 11 and the lengths of the other two side are both positive integers, then the perimeter of a triangle is.............
There are n different positive integers, each one not greater than 2020, with the property that the sum of any three of them is divisible by 39. Find the greatest possible value of n?
A fraction \(\frac{a}{b}\) such that if add a number to both the numerator and the denominator, the value of this fraction is not changed.The fraction \(\frac{a}{b}\)=......
cho m và n thuộc N* thỏa mãn phân số m/n là phân số tối giản; 4m+3n/5m+2n không tối giản. Tìm ƯCLN của 4m+3nvaf 5m+2n
2 năm ko ai trả lời là sao